Tuesday, August 30, 2011

Heat Exchanger - 2

LMTD & Correction Factor (F)
-----------------------------------------------------------------------------------------------------


---------------------------------------------------- (1)
Q = Heat transferred in H-E-X
U = Overall Heat transfer coefficient
F = Correction Factor.
 = Logarithmic Mean Temperature Difference (LMTD)
* LMTD is dependent only on inlet and outlet temperatures and is independent of type of HE used.

where, 

1-stands for Inlet                                                  
2-Stands for Outlet

  • Normal Practice if to calculate LMTD for counter flow and apply correction factor F to it.



Fig.1. LMTD for single pass STHE

Fig.2. LMTD for 1/2 STHE
F (Correction Factor)
  • Shows departure form true counter current flow
  • F is correction factor for multi-pass and crossflow heat exchanger and given for two-pass shell-and-tube heat exchangers in equation (4) below.
  • 0 < F < 1
  • fn { fluid Temperature, no. of passes }
  • F > 0.8, if not then redesign the HEX with more no. of passes or larger LMTD
Find F value:
  1. Find R using:

------------------------- (2)


 
     2. Find P using:








----------------------------------------- (3)




   3. F Value Analytically

From equations (2) and (3) get the values of R & P and substitute in equation (4)



------------------------------------- (4)




4. Graphical F value:


Fig.3. 1-Shell pass, 2 or more even Tube passes

Fig. 4. 2-Shell Pass, Multiples of 4 Tube passes
   
Fig. 5. Divided Shell Flow & Multiples of 2 Tube passes

Fig. 6. Split shell Flow & 2 Tube passes
Example:

Is 1/2 Shell & Tube HE suitable for following condition ? 
Tc1 = 70 deg., Tc2 = 130 deg.
Th1 = 240 deg., Th2 = 120 deg

Solution:









  • From fig. 3 we see that F = 0.735, which is very low value, Since for F < 0.75, F falls rapidly with smal increase in P which implies that basis assumptions made cannot be neglected.
  • Thus, 1/2 Shell & Tube HE is not suitable for this condition.
  • Try Increasing value of LMTD or redesign with more passes.
Calculate, using software, the F values for different shell and tube pass combination here and decide whether the combination is suitable for the following temperature conditions.

The above discussed LMTD & correction factor is useful only when both inlet and outlet temperature conditions are known.

Effectiveness-NTU method is used when one of the temperature is not known.

Effectiveness-NTU method is more useful for Rating rather than design, hence will not be discussed here.
Refer

  • Incropera & dewitt (2001)
  • Engineering Science data unit in their design guides 98003-98007 ( 1998 ).



1 comment:

  1. More information (if anything is missing) is accepted. Be free to contact me.

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